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The dimensions of electrical conductivity is ………… |
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Answer» Correct Answer - `[M^(-1)L^(-3)T^(3)A^(2)]` Electrical conductivity `sigma=J/ErArr [sigma]=[(I//A)/(F//q)]=[(I//A)/(F//it)]=[(I^(2)t)/(FA)]` `=[(A^(2)T)/((MLT^(-2))(L^(2)))]=[M^(-1)L^(-3)T^(3)A^(2)]` |
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