The dimensions of (l)/(KA) are (l is the length of rod, K is the thermal conductivity of rod and A is the area of cross-section of rod)

The dimensions of (l)/(KA) are (l is the length of rod, K is the therm

1.	The dimensions of (l)/(KA) are (l is the length of rod, K is the thermal conductivity of rod and A is the area of cross-section of rod)
Answer» <html><body><p>`[ML^(2)T^(-3)<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(-1)]`<br/>`[M^(-1)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(-2)T^(3)K]`<br/>`[ML^(2)T^(-3)K^(-2)]`<br/>`[<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-3)K^(-1)]`</p>Solution :Rate of heat flow `(<a href="https://interviewquestions.tuteehub.com/tag/dq-959213" style="font-weight:bold;" target="_blank" title="Click to know more about DQ">DQ</a>)/(dt)= (Kad theta)/(l)` <br/> or `(l)/(KA)= (d theta)/(dQ//dt) :. [(l)/(KA)]= [(K)/(ML^(2)T^(-3))]= [M^(-1)L^(-2)T^(3)K]`</body></html>