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The dimensions of `[ML^(-1) T^(-2)]` may correspond toA. Work done by forceB. Linear momentumC. PressureD. Energy per unit volume |
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Answer» Correct Answer - (c,d) Work `= ML^2 T^(-2),` Linear momentum `=MLT^(-1)` pressure `= ML^(-1) T^(-2),` energy per unit volume `=("Energy")/("Volume") = (ML^2T^(-2))/(L^3) = ML^(-1)T^(-2)` Hence option (c ), (d) are correct. |
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