The dimensions of R in the equations Q=Q_(0)(1-e^(-t//RC)) are

1.	The dimensions of R in the equations Q=Q_(0)(1-e^(-t//RC)) are
Answer» `[ML^(2)T^(-3)A^(-2)]` `[ML^(2)T^(-2)A^(-3)]` `[M^(2)L^(2)T^(-3)A^(-2)]` `[ML^(2)T^(-1)A^(-2)]` Solution :`Q=Q_(0)(1-e^(t//RC)`. As `t//RC` is DIMENSIONLESS `thereforeRC=t` or `R=(t)/(C)=(t)/(Q//V)=(V.t)/(Q)` `R=[(ML^(2)T^(-2)])/([AT])([T])/([AT])=[ML^(2)T^(-3)A^(-2)]`

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