1.

The dimensions of the quantity namely (mu_(0)ce^(2))/(2h)where mu_(0) permeability of free space, c - velocity of light, e - electronic charge and h =(h)/(2pi) being Planck's constant

Answer»

`[M^(0)LT]`
`[M^(0)L^(0)T]`
`[M^(0)L^(0)T^(0)]`
`[M^(-2)L^(-1)T^(-3)]`

Solution :The quantity is `(mu_(0)CE^(2))/(2h)= (pimu_(0)ce^(2))/(H)`
`:. c= (1)/(sqrt(mu_(0)epsilon_(0))` or `c^(2)= (1)/(mu_(0)epsilon_(0))`
`:. cmu= (1)/(cepsilon_(0)) :. (pimu_(0)ce^(2))/(h)= (pie^(2))/(cepsilon_(0)h)`
`:. F= (1)/(4piepsilon_(0))(e^(2))/(r^(2))` or `(e^(2))/(r^(2))= Fe^(2)4PI :. (pie^(2))/(cepsilon_(0)h)= (Fr^(2))/(ch) xx 4pi^(2)`
The dimensions of
`(Fr^(2))/(ch)= ([MLT^(-2)][L^(2)])/([LT^(-1)][ML^(2)T^(-1)])= ([ML^(3)T^(-2)])/([ML^(3)T^(-2)])= [M^(0)L^(0)T^(0)]`


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