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The dimensions of torque are same as that ofA. moment of forceB. pressure.C. accelerationD. impulse |
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Answer» Correct Answer - A Torque is expressed as, `tau`=force ( F) `xx` perpendicular distance (r ) So, `[tau]=[F]xx[r]=[MLT^(-2)][L]` `=[ML^(2)T^(-2)]` Now, the dimension of moment of force = force `xx` distance = `[MLT^(-2)]xx[L^(1)] =[ML^(2)T^(-2)]` (b) Dimension of pressure=Force`xx["Area"}^(-2)` (c) Dimension of acceleration = `[M^(0)L^(1)T^(-2)]` (d) Dimension of impulse= [Force] `xx` [time] `=[MLT^(-2)][T^(1)]=MLT^(-1)` As, the torque has dimension `[ML^(2)T^(-2)]` which is correctly matched by the dimensions of moment of force. So, option (a) is correct. |
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