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The dip at a place is delta. For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian. If the axis of the dip needle makes angle `theta` with the magnetic meridian, the apparent dip will be given `tan delta_(1)` which is equal to:A. `tan delta "cosec" theta `B. `tan delta sin theta `C. `tan delta cos theta `D. `tan delta sec theta ` |
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Answer» Correct Answer - A As , ` tan delta=(V)/(H) and tan delta_(1)=(V)/(H cos (90^(@) - theta ))` `= ( tan delta)/( cos (90^(@)- theta ))= tan delta "cosec" theta ` |
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