The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is `B_(1)` . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is ` B_(2)` . The ratio `(B_(1))/(B_(2))` is:A. `(1)/(sqrt(2))`B. 2C. `sqrt(3)`D. `sqrt(2)`

The dipole moment of a circular loop carrying a current I, is m and th

1.	The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is `B_(1)` . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is ` B_(2)` . The ratio `(B_(1))/(B_(2))` is:A. `(1)/(sqrt(2))`B. 2C. `sqrt(3)`D. `sqrt(2)`
Answer» Correct Answer - D

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