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The direction cosine of a normal to the plane 2x – 3y –6z + 14 = 0 are(A) (2/7,-3/7,-6/7)(B) (-2/7,-3/7,6/7)(C) (-2/7,-3/7,-6/7)(D) None of these |
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Answer» Correct option: (A) (2/7,-3/7,-6/7) |
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