The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)), cos beta = (1)/(sqrt(2)) and cos gamma = (3)/(5sqrt(2)), then the vector vecA is

The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)), c

1.	The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)), cos beta = (1)/(sqrt(2)) and cos gamma = (3)/(5sqrt(2)), then the vector vecA is
Answer» `4hat(i)+hat(J)+3HAT(K)` `4hat(i)+5hat(j)+3hat(k)` `4hat(i)-5hat(j)-3hat(k)` `hat(i)+hat(j)-hat(k)` ANSWER :B