The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)),cos beta =(1)/(sqrt(2)) and cos gamma=(3)/(5sqrt(2)) then the vector vecA is

The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)),co

1.	The direction cosines of a vector vecA are cos alpha=(4)/(5sqrt(2)),cos beta =(1)/(sqrt(2)) and cos gamma=(3)/(5sqrt(2)) then the vector vecA is
Answer» `4 HAT(i) + hat(J) + 3hat(K)` `4 hat(i) + 5 hat(j) + 3hat(k)` `4hat(i)- 5hat(j) - 3 hat(k)` `hat(i) + hat(j) - hat(k)` Answer :B