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The direction cosines of the normal to the plane 3x - 3y - 6z - 3 = 0 are(a) 2/7,-3/7,- 6/7(b) 2/7,3/7,6/7(c) -2/7,3/7,- 6/7(d) None of these |
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Answer» Answer is (a) 2/7,-3/7,- 6/7 |
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