1.

The direction of electron flow in certain galvanic cells are given below. (Symbols are not real) i. B → A, ii. E → C, iii. D → E, iv. A → D. a. Arrange the metals A, B, C, D and E in the decreasing order of their reactivity. b. Choose the reaction taking place at ‘C’ in cell (ii) E → C. Give the reason. i. C+ (aq) + le- → C(s) ii. C (s) → C+ (aq) + le-iii. C (s) → C+ (aq) + le-

Answer»

a. B, 

A, 

D, 

E, 

C. 

b. C+ (aq) + le- → C (s) is the correct equation. 

Because ‘E’ has higher reactivity than. So ‘C’undergoes reduction.



Discussion

No Comment Found

Related InterviewSolutions