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The discharging time constant of a circuit consisting of a capacitor is the time taken for the charge in the capacitor to become __________ % of the initial charge.(a) 33(b) 63(c) 37(d) 36 |
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Answer» The correct option is (c) 37 To explain: We know that: Q=Q0(1-e^-t/RC). When RC=t, we have: Q=Q0(1-e^-1) = 0.37*Q0. Hence the time constant is the time taken for the charge in a capacitive circuit to become 0.37 times its initial charge. |
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