1.

The disintegration constant of `.^(238)U` is `1.54 xx 10^(-10) "years"^(-1)`. Calculate the half life period of `.^(238)U`.

Answer» Half life period `t_(1//2) = (0.693)/(lambda)`
since, `lambda = 1.54 xx 10^(-10) "years"^(-1)`
So, `t_(1//2) = (0.693)/(1.54 xx 10^(-10)) = 4.5 xx 10^(9)` years


Discussion

No Comment Found

Related InterviewSolutions