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The disintegration constant of `.^(238)U` is `1.54 xx 10^(-10) "years"^(-1)`. Calculate the half life period of `.^(238)U`. |
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Answer» Half life period `t_(1//2) = (0.693)/(lambda)` since, `lambda = 1.54 xx 10^(-10) "years"^(-1)` So, `t_(1//2) = (0.693)/(1.54 xx 10^(-10)) = 4.5 xx 10^(9)` years |
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