1.

The dispacement of a body is given by `4s=M +2Nt^(4)`, where `M` and `N` are constants. The velocity of the body at the end of `1 s` from the start is .A. `2N`B. `(M+2N)/(4)`C. `2(M_N)`D. `(2M+N)/(4)`

Answer» Correct Answer - A
`s=(M+2Nt^(4))/(4) rArr v=(ds)/(dt) =2Nt^(3) `
Putting `1 s`, we get `v=2 N` .


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