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The displacement equation of a particle performing S.H.M. is x = 10 sin `(2pit+(pi)/(6))`m. Then the initial displacement of a particle isA. 5 mB. 2.5 mC. 0.5 mD. 0.25 m |
Answer» Correct Answer - A `x=10sin(2pit+(pi)/(6))` `=10sin(2pixx0+(pi)/(6))` `=10sin.(pi)/(6)=10xx(1)/(2)=5m` |
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