1.

The displacement equation of a particle performing S.H.M. is x = 10 sin `(2pit+(pi)/(6))`m. Then the initial displacement of a particle isA. 5 mB. 2.5 mC. 0.5 mD. 0.25 m

Answer» Correct Answer - A
`x=10sin(2pit+(pi)/(6))`
`=10sin(2pixx0+(pi)/(6))`
`=10sin.(pi)/(6)=10xx(1)/(2)=5m`


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