InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The displacement equation of a simple harmonic oscillator is given by `y=A sin omegat-Bcos omegat` The amplitude of the oscillator will beA. A - BB. A + BC. `sqrt(A^(2) + B^(2))`D. `(A^(2) + B^(2))` |
|
Answer» Correct Answer - C Displacement equation, `y = A sin omega t - B cos omega t` Let `A = a cos theta and B = a sin theta` So, `A^(2)+B^(2)=a^(2) rArr a = sqrt(A^(2)+B^(2))` Then, `y = a cos theta sin omega t - a sin theta cos omega t = a sin (omega t - theta)` which is the equation of simple harmonic oscillator. The amplitude of the oscillator `= a = sqrt(A^(2)+B^(2))` |
|