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The displacement equation of an oscillator is given by x = 5 sin `(2pit+0.5pi)m`. Then its time period and initial displacement areA. 0.5 s, 5 mB. 1 s, 2.5 mC. 0.5 s, 2.5 mD. 1 s, 5 m

Answer» Correct Answer - D
`x=5sin(2pit+0.5pi)`
`omega=2pi`
`2pin=2pi therefore n=1,T=1s`
`x=5sin(2pixx0+0.5pi)=5sin.(pi)/(2)`
`=5xx1`
`=5m`


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