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The displacement equation of an oscillator is given by x = 5 sin `(2pit+0.5pi)m`. Then its time period and initial displacement areA. 0.5 s, 5 mB. 1 s, 2.5 mC. 0.5 s, 2.5 mD. 1 s, 5 m |
Answer» Correct Answer - D `x=5sin(2pit+0.5pi)` `omega=2pi` `2pin=2pi therefore n=1,T=1s` `x=5sin(2pixx0+0.5pi)=5sin.(pi)/(2)` `=5xx1` `=5m` |
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