1.

The displacement (in metre) of a particle varies with time (in second) according to the equation y =- (2)/(3) t ^(2) + 16 t +2.How long does the particle take to come to rest ?

Answer»

12 s
8 s
16 s
10 s

Solution :The DISPLACEMENT of a PARTICLE
`y =- 2/3 t ^(2) + 16 t +2`
`THEREFORE` Velocity `U = (dy)/(DT) = (d)/(dt) [- (2)/(3) t ^(2) + 16 t +2]`
`therefore v = -(4)/(3) t + 16`
When a particle is at rest, v =0
`therefore 0=- (4)/(3) t + 16`
`therefore 4/3 t = 16`
`therefore t = 12s.`


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