Saved Bookmarks
| 1. |
The displacement (in metre) of a particle varies with time (in second) according to the equation y =- (2)/(3) t ^(2) + 16 t +2.How long does the particle take to come to rest ? |
|
Answer» 12 s `y =- 2/3 t ^(2) + 16 t +2` `THEREFORE` Velocity `U = (dy)/(DT) = (d)/(dt) [- (2)/(3) t ^(2) + 16 t +2]` `therefore v = -(4)/(3) t + 16` When a particle is at rest, v =0 `therefore 0=- (4)/(3) t + 16` `therefore 4/3 t = 16` `therefore t = 12s.` |
|