The displacement of a body is given byx = 2t^(3) - 6t^(2) + 12t + 6. The acceleration of body is zero at time ti is equal to :

The displacement of a body is given byx = 2t^(3) - 6t^(2) + 12t + 6. T

1.	The displacement of a body is given byx = 2t^(3) - 6t^(2) + 12t + 6. The acceleration of body is zero at time ti is equal to :
Answer» 3s 2s 1S 10s Solution :`x = 2t^(2) - 6t^(2) + 12T +6` `v = (dx)/(dt) = (d)/(dt) (2t^(3) - 6t^(2) +12t +6)` `= 2 XX 3t^(2) - 6 xx 2t +12` `= 6t^(2) - 12t + 12` `a = (dv)/(dt) = (d)/(dt) (6t^(2) - 12t+12)` `= 6 xx 2t - 12` `= 12t - 12` Sincea = 0 12t - 12 = 0 12t = 12 `:. t = (12)/(12) = 1s` t = 1s