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The displacement of a particle after time t is given by `x = (k // b^(2)) (1 - e^(-bi))`. Where b is a constant. What is the acceleration fo the particle ?A. `ke^(-bt)`B. `- ke^(-bt)`C. `(k)/(b^(2))e^(bt)`D. `(- k)/(b^(2))e^(-bt)` |
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Answer» Correct Answer - B `v = (dx)/(dt) = (k)/(b^(2)) xx e(-bt) xx b` `(dv)/(dt) = -ke^(-bt)` |
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