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The displacement of a particle executing SHM is given by `Y=5 " sin "(4t+(pi)/(3))` If T is the time period and the mass of the particle is 2g, the kinetic energy of the particle When t=`(T)/(4)` is given by-A. 0.4JB. 0.5JC. 3JD. 0.3J |
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Answer» Correct Answer - D `V=(dy)/(dt) =5 xx 4 "cos" (4((T)/(4))+(pi)/(3))` `V=20 " cos " (T+(pi)/(3))` as y = t sin `(4t + (pi)/(3))` Compare with y = A sin `(omegat + (pi)/(3))` `omega =4 rArr T=(2pi)/(4) = (pi)/(3)` So that V 20 cos`((pi)/(2)+(pi)/(3))` `=- 20 "sin" (pi)/(3) =- 10 sqrt(3)` `KE =1/2" mu"^(2) =1/2 (10 sqrt(3))^(2) xx 2 xx10^(-3) =0.3 J` |
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