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The displacement of a particle is given by x = (t-2)^(2)where x is in metre and t in second. The distance covered by the particle in first 4 seconds is

Answer» <html><body><p>4m <br/>8m <br/>12m <br/>16m </p>Solution :Given, `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = (t-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) ^(2)` <br/> Velocity, `v = (dx)/(dt) = (d)/(dt)(t-2) ^(2) = 2 (t -2) m//s` <br/> Acceleration,` a = (dv)/(dt) = (d)/(dt) [2 (t -2)]` <br/> `=2 [1-0]=2m//s^(2)` <br/> When,` t =0 implies v=- 4m//s` <br/> `t = 2s implies v =0 m//s` <br/> `t = 4s implies v = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> m//s`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E04_005_S01.png" width="80%"/><br/> u-t graphs is shown in adjacent diagram. <br/> Distance travelled = area of the <a href="https://interviewquestions.tuteehub.com/tag/graph-17327" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPH">GRAPH</a> <br/> = area OAC + area ABD <br/> `= (<a href="https://interviewquestions.tuteehub.com/tag/4xx-1883349" style="font-weight:bold;" target="_blank" title="Click to know more about 4XX">4XX</a> 2)/(2) + 1/2xx 2 xx 4 =8m`</body></html>


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