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The displacement of a particle is `s = (a+bt)^(6)`, where a and b are constants. Find acceleration of the particle as a function of time.A. `30b^(2)(a+bt)^(4)`B. `30b^(2)(a+bt)^(3)`C. `6b^(2)(a+bt)^(5)`D. `30b^(2)(a+bt)^(5)` |
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Answer» Correct Answer - C Let F be the force of air resistance. For the upward motion Facts downward. Let `a_(1)` = retardation (downward acceleration). `mg+F=ma_(1) " or "a_(1) = g +(F)/(m)` Thus `a_(1) gt a_(2)` Let h = maximum height reached `h=(1)/(2)a_(1)t_(1)^(2)=(1)/(2)a_(2)t_(1)^(2)` |
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