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The displacement of a particle making S.H.M. is given by `x=6cos(100t+(pi)/(4))m` then the frequency isA. `1.592 Hz`B. `15.92 Hz`C. `159.2 Hz`D. `1592 Hz` |
Answer» Correct Answer - B `x=6cos(100t+(pi)/(4))` `omega=100` `2pin=100` `n=(100)/(2pi)=(50)/(pi)=15.92Hz`. |
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