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The displacement of a particle moving along x-axis with respect to time t is x = at + bt^(2) - ct^(3)The dimensions of care

Answer» <html><body><p>`[T^(-3)]`<br/>`[LT^(-2)]`<br/>`[LT^(-3)]`<br/>`[LT^(3)]`</p>Solution :`x= at+ bt^(2)-<a href="https://interviewquestions.tuteehub.com/tag/ct-411317" style="font-weight:bold;" target="_blank" title="Click to know more about CT">CT</a>^(3)` <br/> Each term on <a href="https://interviewquestions.tuteehub.com/tag/rhs-614248" style="font-weight:bold;" target="_blank" title="Click to know more about RHS">RHS</a> <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> have dimensions of x.<br/> `:. [ct^(3)]= [x]` or `[c]= ([x])/([t^(3)])= ([<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>])/([T^(3)])= [LT^(-3)]`</body></html>


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