The displacement of a particle moving along x-axis with respect to times is given by x=at+bt^(2)-ct^(3). The dimensions of b are

The displacement of a particle moving along x-axis with respect to tim

1.	The displacement of a particle moving along x-axis with respect to times is given by x=at+bt^(2)-ct^(3). The dimensions of b are
Answer» `L^(0)T^(-3)` LT `LT^(-2)` `LT^(-3)` SOLUTION :Accordingto principle of homogeneity the DISPLACEMENT is `X = at+bt^2 -ct^3` The dimensionally . `[L] = [LT^(-1)] + [T] + [ LT^(-2)] - [LT^(-3)] [T^3]` `therefore ` the dimension of .b. is `LT^(-2)`