The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t. The amplitude and maximum velocity of a particle respectively are………….

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t. The

1.	The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t. The amplitude and maximum velocity of a particle respectively are………….
Answer» `5,10` `3,2` `4,2` `3,4` Solution :`x= 3 sin 2t + 4 cos 2t` `a_(1)= 3, a_(2)= 4" and "PHI= (pi)/(2)` `THEREFORE A= SQRT(a_(1)^(2)+a_(2)^(2))= sqrt(3^(2)+4^(2))= 5` unit `implies v_("max")= A omega` `= 5xx 2 = 10`.