The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t t

1.	The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……
Answer» `7` `1` `5` `12` Solution :Comparing given equation `y= A sin omega t+ B cos omega t` with equation `y= 3sin omega t+4 cos omega t` `A= 3" and "B= 4` AMPLITUDE `a= sqrt(A^(2)+B^(2))` `= sqrt((3)^(2)+(4)^(2))` `THEREFORE a= 5`.