The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61). For this, what are the value of time period.

The displacement of a simple harmonic oscillator is given by y= 0.40 s

1.	The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61). For this, what are the value of time period.
Answer» Solution :Comparing `y= 0.40 SIN (440t + 0.61)" with " y= A sin (OMEGA t+ phi)` Periodic time `T= (2pi)/(omega)` `=(2xx22)/(440xx7)` `= 0.01428 THEREFORE T apporx 0.0143s` Periodic time `T= (1)/(f)` `=(1)/(70) = 0.01428 therefore T APPROX 0.0143s`.