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The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61). For this, what are the value of initial phase? |
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Answer» SOLUTION :Comparing `y= 0.40 SIN (440T + 0.61)" with " y= A sin (OMEGA t+ phi)` INITIAL phase `phi = 0.61 rad`. |
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