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The displacement of a simple harmonic oscillator is given by x = 4 cos `(2pit+pi//4)m`. Then velocity of the oscillator at t = 2 s isA. `4pisqrt(2)m//s`B. `(4pi)/(sqrt(2))m//s`C. `(sqrt(2)pi)/(4)m//s`D. `(4sqrt(2))/(pi)m//s` |
Answer» Correct Answer - A `x=4cos(2pit+(pi)/(4))` `(dx)/(dt)=4xx2pisin(2pit+(pi)/(4))` `v=8pixxsin(2pixx2+(pi)/(4))` `=8pisin.(pi)/(4)` `=8pixx(1)/(sqrt(2))=(4sqrt(2)xxsqrt(2)pi)/(sqrt(2))=4sqrt(2)pi`. |
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