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The displacement of a simple harmonic oscillator is, x = 5 sin `(pit//3) m`. Then its velocity at t = 1 s, isA. `(pi)/(6)m//s`B. `(5pi)/(6)m//s`C. `(6pi)/(6)m//s`D. `(pi)/(2)m//s` |
Answer» Correct Answer - B `x=5sin.(pit)/(3)` `(dx)/(dt)=5xx(pi)/(3)cos.(pi)/(3)t` `v=(5pi)/(3)xxcos((pi)/(3)xx1)=(5pi)/(3)xx(1)/(2)` `=(5pi)/(6)m//s` |
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