1.

The displacement of a simple harmonic oscillator is, x = 5 sin `(pit//3) m`. Then its velocity at t = 1 s, isA. `(pi)/(6)m//s`B. `(5pi)/(6)m//s`C. `(6pi)/(6)m//s`D. `(pi)/(2)m//s`

Answer» Correct Answer - B
`x=5sin.(pit)/(3)`
`(dx)/(dt)=5xx(pi)/(3)cos.(pi)/(3)t`
`v=(5pi)/(3)xxcos((pi)/(3)xx1)=(5pi)/(3)xx(1)/(2)`
`=(5pi)/(6)m//s`


Discussion

No Comment Found

Related InterviewSolutions