The displacement of object is proportional to cube of the time, then a

1.	The displacement of object is proportional to cube of the time, then acceleration is .....
Answer» constant, but not zero. increasing with time. zero. decreasing with time. Solution :`y prop t ^(3)` `therefore y = KT ^(3),` where k is constant `therefore V = (dy)/(DT) = (d)/(dt) (Kt ^(3))` `therefore v = 3 Kt ^(2)` `therefore a = (dv)/(dt) = (d 3Kt ^(2))/(dt) = 6kt` `therefore a prop t[because6k` constant] `therefore` ACCELERATION INCREASE with time .

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