The displacement of particle with respect to time is s = 3^(t3) - 7t^(2) + 5t + 8 where s is in m and t is in s, then acceleration of particle at t = ls is

The displacement of particle with respect to time is s = 3^(t3) - 7t^(

1.	The displacement of particle with respect to time is s = 3^(t3) - 7t^(2) + 5t + 8 where s is in m and t is in s, then acceleration of particle at t = ls is
Answer» `14 MS^(-2)` `18 ms ^(-2)` `32 ms^(-2)` zero Solution :`s =3T ^(3) + 7t ^(2) + 5t +8` `therefore v = 9t ^(2) + 14 t +5` `and a = 18 t + 14` Now` t=1s` `a (1) = 18 +14` `therefore a (1) = 32 ms ^(-12`