The displacement of SHM particle is x(t)= A cos (omega t+ phi). Its initial displacement is 1 cm and initial velocity is pi(cm)/(sec) and angular frequency is pi s^(-1). Find amplitude.

The displacement of SHM particle is x(t)= A cos (omega t+ phi). Its in

1.	The displacement of SHM particle is x(t)= A cos (omega t+ phi). Its initial displacement is 1 cm and initial velocity is pi(cm)/(sec) and angular frequency is pi s^(-1). Find amplitude.
Answer» `1 cm` `SQRT(2) cm` `2 cm` `2.5 cm` Solution :`V= PI cm"/"s""x=1 cm" and " OMEGA pi"/"s` are given `v= omega sqrt(A^(2)-x^(2)) implies pi = pi sqrt(A^(2)-1)` `therefore 1= A^(1) -1 implies A= sqrt(2) cm`.