The displacement of two identical particles executing SHM are represented by equations x_(1)= 4sin(10t+ (pi)/(6))and x_(2) =5 cosomega t For what value of omega energy of both the particles is same

The displacement of two identical particles executing SHM are represen

1.	The displacement of two identical particles executing SHM are represented by equations x_(1)= 4sin(10t+ (pi)/(6))and x_(2) =5 cosomega t For what value of omega energy of both the particles is same
Answer» Solution :`E= (1)/(2)mA^(2)omega^(2) i.e., E PROP (Aomega)^(2)` `(A_(1)omega_(1))^(2)= (A_(2)omega_(2))^(2) "" A_(1)omega_(1)= A_(2)omega_(2)` `4 xx 10 = 5 xx omega"" omega= 8` UNIT