InterviewSolution
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InterviewSolution
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The displacement of two particles executing SHM are represented by equations, `y_(1)=2 sin (10 t + theta), y_(2)=3 cos 10 t`. The phase difference between the velocity of these particles isA. `theta`B. `-theta`C. `theta + pi//2`D. `theta - pi//2 ` |
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Answer» Correct Answer - D We can find the velocities, `V_(1) = (dy_(1))/(dt) = 2 xx 10 cos (10 t + theta)` and `V_(2) = - 3 xx 10 sin 10 t = 30 cos (10 t + pi//2)` `therefore` Phase difference `= (10 t + theta) - (10 t + pi//2)= theta - pi//2` |
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