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The displacement r of a particle varies with time as x=4t^(2)-15t+25Find the position, velocity and acceleration of the particle at t = 0 |
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Answer» Solution :Position, x=25 Velocity `=(dx)/(dt)=8t-15` `t=0,v=0-15=-15m//s` ACCELERATION `a=(DV)/(dt)=8ms^(-2)`. |
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