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The displacement x in meters of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in seconds by the equation `t=sqrtx+3`, , the work done by the force (in J) in first six seconds is :-A. 18 mB. zeroC. 9 m/2D. 36 m |
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Answer» Correct Answer - B `t=sqrtx+3` `x=(t-3)^(2)` `x=t^(2)-6t+9` `V=(dx)/(dt)=2t-6` `t=0" "u=-6` `t=6" "v=12-6=6` `W=(1)/(2)xxm|36-36|=0` |
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