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The displacement x is in centimeter of an oscillating particle varies with time t in seconds as x = 2 cos `[0.05pi t+(pi//3)]`. Then the magnitude of the maximum acceleration of the particle will beA. `(pi)/(2)cm//s^(2)`B. `(pi)/(4)cm//s^(2)`C. `(pi^(2))/(200)cm//s^(2)`D. `(pi^(2))/(4)cm//s^(2)` |
Answer» Correct Answer - C Acceleration max `=(Aomega^(2))` `=2(0.05pi)^(2)` `=2xx25 pi^(2)xx10^(-4)` `=50pi^(2)xx10^(-4)` `=0.5pi^(2)xx10^(-2)` `=(pi^(2))/(200)` |
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