The displacement x of a particle at the instant when its velocity v is given by v=sqrt(3x+16). Find its acceleration and initial velocity

The displacement x of a particle at the instant when its velocity v is

1.	The displacement x of a particle at the instant when its velocity v is given by v=sqrt(3x+16). Find its acceleration and initial velocity
Answer» Solution :`V=sqrt(3x+16)ORV^(2)=3x+16` or `v^(2)-16=3x` COMPARING with `v^(2)-u^(2)=2AS`, we GET, `u=4` units, `2a=3` or `a=1.5` units