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The displacement `x` of a particle in motion is given in terms of time by `x(x-4) =1 -5 cos omegat`A. the particle executes `SHM`B. the particle executes oscillatory motion which is not `SHM`C. the motion of the particle is neither oscillatory nor simple harmonicD. the particle is not acted upon by a fprce when it is at `x = 4` |
Answer» Correct Answer - A `(d^(2)(x-2))/(dt^(2)) = (-omega^(2))/(4)(x-2)` `:.` The particle executes `SHM` |
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