The displacement (x) of a particle is given by x= a sin (bt+c) where a, b and c are constants of motion. Select the incorrect statement from the following .

The displacement (x) of a particle is given by x= a sin (bt+c) where a

1.	The displacement (x) of a particle is given by x= a sin (bt+c) where a, b and c are constants of motion. Select the incorrect statement from the following .
Answer» The energy ofthe partical in simple harmonic motion remains constant The VELOCITY of the particle is zero at `x=+-a`. The ACCELERATION of the particle is zero at `x=+-a`. The motion REPRESENTED by the given equation rpeats itself a time internal `(2pi)/(b)` Solution :Acceleration of the partile is MAXIMUM at `a=+-a`.