The displacement y (in metre) of a body varies with time t (in seconds) as y = -(2)/(3)t^(2)16t+2.The body comes to rest in atime

The displacement y (in metre) of a body varies with time t (in seconds

1.	The displacement y (in metre) of a body varies with time t (in seconds) as y = -(2)/(3)t^(2)16t+2.The body comes to rest in atime
Answer» 8s 10s 12s 14s Solution : According to the QUEATION `y = -(2)/(3)t^(2)+ 16t+2` Compare it with STANDARD equation: `X= ut+(1)/(2)at^(2)` We have : `u=16ms^(-1), (a)/(2)=-(2)/(3)` or `a=-(4)/(3)ms^(-2)` for a body to come to rest , V = 0 Using above values in V = u at we get `0=16+(-(4)/(3))t` or t =12SEC