The displacementequation of a particle executing simple harmonic motion is x= (5m) sin ( pi t + pi/2) . Find amplitude , time period and maximum speed ?

The displacementequation of a particle executing simple harmonic motio

1.	The displacementequation of a particle executing simple harmonic motion is x= (5m) sin ( pi t + pi/2) . Find amplitude , time period and maximum speed ?
Answer» Solution :Comparing with the EQUATION x=`A sin (omega t + PHI)` , we have amplitude = 5M Time PERIOD `=(2pi)/(omega) = (2pi)/(pi) = 2s` , maximum speed `=A omega =5 xx pi= 5 pi` m/s