The dissociation constant of a weak acid is 10^(-6) . Then the P^(H)of 0.01 Nof that acid is

The dissociation constant of a weak acid is 10^(-6) . Then the P^(H)of

1.	The dissociation constant of a weak acid is 10^(-6) . Then the P^(H)of 0.01 Nof that acid is
Answer» Solution :Given` pH = 4, [H^(+)] = 10^(-4)`M `[H^(+) ]=sqrt(K_a C), 10^(-4)= sqrt( 10^(-7) C )` INITIAL CONCENTRATION of the WEAK acid, HA = C = 0.1 mol `L^(-1)` Final concentration of the acid` HA=( 10 xx 0.1 ) /( 1000 ) = 10^(-3) mol L^(-1)` Final `[H^(+) ]= sqrt(K_a C) =sqrt(10^(-7) xx 10^(-3)) = 10^(-5) M` Final `pH = -log 10^(-5)` = 5.