The dissociation of CO2 can be expressed as2Co 2Co +O2 . lf the 2 mol

1.	The dissociation of CO2 can be expressed as2Co 2Co +O2 . lf the 2 mol of CO2 is takeninitially and 40% of the CO2 is dissociatedcompletely. What is the total number of moles atequilibrium:-(1) 2.4 (2) 2.0 (3) 1.2 (4) 5
Answer» ANSWER: option 1 is correct Explanation: 2CO2 ------> 2CO + O2 Initial moles of CO2 are two Initial moles of CO and O2 are zero At EQUILIBRIUM degree of dissociation a = 40%=0.4 for the given reaction equilibrium moles of CO2 = 2—2A = 2—2(0.4)= 1.2 equilibrium moles of CO = 2a = 2(0.4)= 0.8 equilibrium moles of O2 = a = 0.4 therefore total moles at equilibrium are 1.6+0.8+0.4=2.8

The dissociation of CO2 can be expressed as2Co 2Co +O2 . lf the 2 mol of CO2 is takeninitially and 40% of the CO2 is dissociatedcompletely. What is the total number of moles atequilibrium:-(1) 2.4 (2) 2.0 (3) 1.2 (4) 5

Answer»

option 1 is correct

Explanation:

2CO2 ------> 2CO + O2

Initial moles of CO2 are two

Initial moles of CO and O2 are zero

At EQUILIBRIUM degree of dissociation a = 40%=0.4

for the given reaction

equilibrium moles of CO2 = 2—2A = 2—2(0.4)= 1.2

equilibrium moles of CO = 2a = 2(0.4)= 0.8

equilibrium moles of O2 = a = 0.4

therefore total moles at equilibrium are

1.6+0.8+0.4=2.8