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The dissolution of `Al(OH)_(3)` by a solution of `NaOH` results in the formation ofA. `[Al(H_(2)O)_(4)(OH)]^(2+)`B. `[Al(H_(2)O)_(3)(OH)_(3)]`C. `[Al(H_(2)O)_(2)(OH)_(4)]^(-)`D. `[Al(H_(2)O_(6)](OH)_(3)` |
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Answer» Correct Answer - C `Al(OH)_(3)+OH^(-) rarr [Al(OH)_(4)]^(-)` or `[Al(OH)_(4)(H_(2)O)_(2)]^(-)` |
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